Math Question
![On a map, the scale shown is 1 inch : 5 miles. If a wildlife refuge is 50 square miles, what is the area of the refuge on the map?
Use the proportion to solve for \( x \).
\& \( \frac{1 \mathrm{in.}^{2}}{25 \mathrm{mi}^{2}}=\frac{\mathrm{xin} .^{2}}{50 \mathrm{mi}^{2}} \)
The area of the wildlife refuge is [?] square inches on the map.](https://d3hlidq5bf9vg0.cloudfront.net/app-server-student/2022/3/28/1511b268-373d-4252-a4fb-a5b59ea6a7ad.png "On a map, the scale shown is 1 inch : 5 miles. If a wildlife refuge is 50 square miles, what is the area of the refuge on the map?
Use the proportion to solve for \( x \).
\& \( \frac{1 \mathrm{in.}^{2}}{25 \mathrm{mi}^{2}}=\frac{\mathrm{xin} .^{2}}{50 \mathrm{mi}^{2}} \)
The area of the wildlife refuge is [?] square inches on the map.")
Solution
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