Math Question

9. A ball is thrown upward with an initial velocity of 40 feet per second from ground level. The height of the ball, in feet, after \( t \) seconds is given by \( h=-16 t^{2}+40 t \). At the same time, a balloon is rising at a constant rate of 10 feet per second. Its height, in feet, after \( t \) seconds is given by \( h=10 t \). Find the time it takes for the ball and the balloon to reach the same height.



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