AIR MATH

Math Question

Identify the equation of a circle that has a radius of 6 and center at \( (3,-5) \).
\( (x-3)^{2}+(y+5)^{2}=9 \)
\( (x+3)^{2}+(y-5)^{2}=6 \)
\( (x+3)^{2}+(y-5)^{2}=36 \)
\( (x-3)^{2}+(y+5)^{2}=36 \)

Solution

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