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Math Question

What are the zeros of the quadratic function \( f(x)=6 x^{2}+12 x-7 ? \) \( x=-1-\sqrt{\frac{13}{6}} \) and \( x=-1+\sqrt{\frac{13}{6}} \) \( x=-1-\frac{2}{\sqrt{3}} \) and \( x=-1+\frac{2}{\sqrt{3}} \) \( x=-1-\sqrt{\frac{7}{6}} \) and \( x=-1+\sqrt{\frac{7}{6}} \) \( x=-1-\frac{1}{\sqrt{6}} \) and \( x=-1+\frac{1}{0 \sqrt{6}} \)

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