The first two steps in determining the solution set of the system of equations, $ y=x^{2}-2 x-3 $ and $ y=-x+3 $, algebraically are shown in the table.
\begin{tabular}{|c|c|}
\hline Step & Equation \
\hline Step 1 & $ x^{2}-2 x-3=-x+3 $ \
\hline Step 2 & $ 0=x^{2}-x-6 $ \
\hline
\end{tabular}
Which represents the solution(s) of this system of equations?
$ (3,0) $ and $ (-2,5) $
$ (-6,9) $ and $ (1,2) $
$ (-3,6) $ and $ (2,1) $
$ (6,-3) $ and $ (-1,4) $

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