Math Question

6. A ball is thrown upward from a person standing in his room, which is a height of 18 feet. It is thrown with an initial velocity of \( 64 \mathrm{ft} / \mathrm{s} \). The motion of the ball is modeled by the equation \( \mathrm{h}=18+64 \mathrm{t}-16 \mathrm{t}^{2} \), where \( \mathrm{h} \) is the height of the ball above the ground in feet after \( \mathrm{t} \) seconds.
a) At what time does the ball reach its maximum height?
b) What is the maximum height?
c) At what time does the ball hit the ground?



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