$ f(x)=(5 x+3)(x-2)(3 x+7)(x+5) $ has zeros at $ x=-5, x=-\frac{7}{3}, x=-\frac{3}{5} $, and $ x=2 $
What is the sign of $ f $ on the interval $ -\frac{7}{3}

Question

$ f(x)=(5 x+3)(x-2)(3 x+7)(x+5) $ has zeros at $ x=-5, x=-\frac{7}{3}, x=-\frac{3}{5} $, and $ x=2 $
What is the sign of $ f $ on the interval $ -\frac{7}{3}<x<-\frac{3}{5} $ ?

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