AIR MATH

Math Question

Here are Xavier's bowling scores:
\[
135,140,130,190,112,200,185,172 \text {, }
\]
\[
163,151,149
\]
What is the variance rounded to the nearest tenth?
\[
\begin{aligned}
\sigma^{2} &=\frac{\sum(x-\text { mean })^{2}}{n} \\
\sigma^{2} &=[?]
\end{aligned}
\]

Solution

solution

AIR MATH homework app,
absolutely FOR FREE!

  • AI solution in just 3 seconds!
  • Free live tutor Q&As, 24/7
  • Word problems are also welcome!
appstoreplaystore

Scan the QR code below
to download AIR MATH!

qrcode