AIR MATH

Math Question

You are helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 8 feet per second. If the acceleration due to gravity \( (g) \) is \( 32 \mathrm{feet} / \) second \( ^{2} \), how far above the ground \( (h) \) was the hammer when you dropped it? Use the formula:
\[
v=\sqrt{2 g h}
\]
A. \( 8.0 \) feet
B. \( 2.0 \) feet
C. \( 1.0 \) foot
D. \( 16.0 \) feet

Solution

solution

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