AIR MATH

Math Question

If you rolled two dice, what is the probability \( \because \) that you would roll a sum of 3 ?
\begin{tabular}{rrrrrrr}
\( \therefore \) first & \multicolumn{1}{c}{ second } & 2 & 3 & 4 & 5 & 6 \\
1 & 1,1 & 1,2 & 1,3 & 1,4 & 1,5 & 1,6 \\
2 & 2,1 & 2,2 & 2,3 & 2,4 & 2,5 & 2,6 \\
3 & 3,1 & 3,2 & 3,3 & 3,4 & 3,5 & 3,6 \\
4 & 4,1 & 4,2 & 4,3 & 4,4 & 4,5 & 4,6 \\
5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & 5,6 \\
6 & 6,1 & 6,2 & 6,3 & 6,4 & 6,5 & 6,6 \\
\multicolumn{6}{c}{ Probability \( =\frac{\text { Desired Outcome }}{\text { All Outcomes }} \)}
\end{tabular}
Simplify your fraction, then enter the numerator.

Solution

solution

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